Optimal. Leaf size=136 \[ \frac{a \left (a^2-2 b^2\right ) \cos (c+d x)}{2 d}+\frac{b \left (2 a^2-b^2\right ) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} b x \left (12 a^2+b^2\right )-\frac{a^3 \tanh ^{-1}(\cos (c+d x))}{d}+\frac{a \cos (c+d x) (a+b \sin (c+d x))^2}{4 d}+\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 d} \]
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Rubi [A] time = 0.413054, antiderivative size = 136, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.28, Rules used = {2889, 3050, 3049, 3033, 3023, 2735, 3770} \[ \frac{a \left (a^2-2 b^2\right ) \cos (c+d x)}{2 d}+\frac{b \left (2 a^2-b^2\right ) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} b x \left (12 a^2+b^2\right )-\frac{a^3 \tanh ^{-1}(\cos (c+d x))}{d}+\frac{a \cos (c+d x) (a+b \sin (c+d x))^2}{4 d}+\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 d} \]
Antiderivative was successfully verified.
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Rule 2889
Rule 3050
Rule 3049
Rule 3033
Rule 3023
Rule 2735
Rule 3770
Rubi steps
\begin{align*} \int \cos (c+d x) \cot (c+d x) (a+b \sin (c+d x))^3 \, dx &=\int \csc (c+d x) (a+b \sin (c+d x))^3 \left (1-\sin ^2(c+d x)\right ) \, dx\\ &=\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 d}+\frac{1}{4} \int \csc (c+d x) (a+b \sin (c+d x))^2 \left (4 a+b \sin (c+d x)-3 a \sin ^2(c+d x)\right ) \, dx\\ &=\frac{a \cos (c+d x) (a+b \sin (c+d x))^2}{4 d}+\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 d}+\frac{1}{12} \int \csc (c+d x) (a+b \sin (c+d x)) \left (12 a^2+9 a b \sin (c+d x)-3 \left (2 a^2-b^2\right ) \sin ^2(c+d x)\right ) \, dx\\ &=\frac{b \left (2 a^2-b^2\right ) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a \cos (c+d x) (a+b \sin (c+d x))^2}{4 d}+\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 d}+\frac{1}{24} \int \csc (c+d x) \left (24 a^3+3 b \left (12 a^2+b^2\right ) \sin (c+d x)-12 a \left (a^2-2 b^2\right ) \sin ^2(c+d x)\right ) \, dx\\ &=\frac{a \left (a^2-2 b^2\right ) \cos (c+d x)}{2 d}+\frac{b \left (2 a^2-b^2\right ) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a \cos (c+d x) (a+b \sin (c+d x))^2}{4 d}+\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 d}+\frac{1}{24} \int \csc (c+d x) \left (24 a^3+3 b \left (12 a^2+b^2\right ) \sin (c+d x)\right ) \, dx\\ &=\frac{1}{8} b \left (12 a^2+b^2\right ) x+\frac{a \left (a^2-2 b^2\right ) \cos (c+d x)}{2 d}+\frac{b \left (2 a^2-b^2\right ) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a \cos (c+d x) (a+b \sin (c+d x))^2}{4 d}+\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 d}+a^3 \int \csc (c+d x) \, dx\\ &=\frac{1}{8} b \left (12 a^2+b^2\right ) x-\frac{a^3 \tanh ^{-1}(\cos (c+d x))}{d}+\frac{a \left (a^2-2 b^2\right ) \cos (c+d x)}{2 d}+\frac{b \left (2 a^2-b^2\right ) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a \cos (c+d x) (a+b \sin (c+d x))^2}{4 d}+\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 d}\\ \end{align*}
Mathematica [A] time = 0.289677, size = 129, normalized size = 0.95 \[ \frac{8 a \left (4 a^2-3 b^2\right ) \cos (c+d x)+24 a^2 b \sin (2 (c+d x))+48 a^2 b c+48 a^2 b d x+32 a^3 \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )-32 a^3 \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )-8 a b^2 \cos (3 (c+d x))-b^3 \sin (4 (c+d x))+4 b^3 c+4 b^3 d x}{32 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.091, size = 150, normalized size = 1.1 \begin{align*}{\frac{{a}^{3}\cos \left ( dx+c \right ) }{d}}+{\frac{{a}^{3}\ln \left ( \csc \left ( dx+c \right ) -\cot \left ( dx+c \right ) \right ) }{d}}+{\frac{3\,{a}^{2}b\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2\,d}}+{\frac{3\,{a}^{2}bx}{2}}+{\frac{3\,{a}^{2}bc}{2\,d}}-{\frac{a{b}^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{d}}-{\frac{{b}^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{3}\sin \left ( dx+c \right ) }{4\,d}}+{\frac{{b}^{3}\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{8\,d}}+{\frac{{b}^{3}x}{8}}+{\frac{{b}^{3}c}{8\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.15422, size = 136, normalized size = 1. \begin{align*} -\frac{32 \, a b^{2} \cos \left (d x + c\right )^{3} - 24 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} a^{2} b -{\left (4 \, d x + 4 \, c - \sin \left (4 \, d x + 4 \, c\right )\right )} b^{3} - 16 \, a^{3}{\left (2 \, \cos \left (d x + c\right ) - \log \left (\cos \left (d x + c\right ) + 1\right ) + \log \left (\cos \left (d x + c\right ) - 1\right )\right )}}{32 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.63186, size = 297, normalized size = 2.18 \begin{align*} -\frac{8 \, a b^{2} \cos \left (d x + c\right )^{3} - 8 \, a^{3} \cos \left (d x + c\right ) + 4 \, a^{3} \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) - 4 \, a^{3} \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) -{\left (12 \, a^{2} b + b^{3}\right )} d x +{\left (2 \, b^{3} \cos \left (d x + c\right )^{3} -{\left (12 \, a^{2} b + b^{3}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.24492, size = 396, normalized size = 2.91 \begin{align*} \frac{8 \, a^{3} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right ) +{\left (12 \, a^{2} b + b^{3}\right )}{\left (d x + c\right )} - \frac{2 \,{\left (12 \, a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 8 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{6} + 24 \, a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{6} + 12 \, a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 7 \, b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 24 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} + 24 \, a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 12 \, a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 7 \, b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 24 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 8 \, a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 12 \, a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 8 \, a^{3} + 8 \, a b^{2}\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{4}}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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